Detailed Lemmas on Zeros of Dirichlet L-Functions in Ω

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Author:

(1) Yitang Zhang.

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Table of Links

Abstract & Introduction
Notation and outline of the proof
The set Ψ1
Zeros of L(s, ψ)L(s, χψ) in Ω
Some analytic lemmas
Approximate formula for L(s, ψ)
Mean value formula I
Evaluation of Ξ11
Evaluation of Ξ12
Proof of Proposition 2.4
Proof of Proposition 2.6
Evaluation of Ξ15
Approximation to Ξ14
Mean value formula II
Evaluation of Φ1
Evaluation of Φ2
Evaluation of Φ3
Proof of Proposition 2.5

Appendix A. Some Euler products

Appendix B. Some arithmetic sums

References

4. Zeros of L(s, ψ)L(s, χψ) in Ω

In this section we prove Proposition 2.2. We henceforth assume that ψ(mod p) ∈ Ψ1. This assumption will not be repeated in the statements of Lemma 4.1-4.8.


We begin by proving some consequences of the inequalities (3.4)-(3.6).


Lemma 4.1. Let


Proof. By the Stieltjes integral we may write


Hence, by partial integration,


For G(s, ψ) an entirely analogous bound is valid. The result now follows by (3.4).


Lemma 4.2. If s ∈ Ω1, then


Proof. We have


Thus, similar to (4.2), by partial integration we obtain


Lemma 4.3. Let


We proceed to establish an approximate formula for L(s, ψ)L(s, χψ). For this purpose we first introduce a weight g(x) that will find application at various places. Let


with


We may write


Since


it follows, by changing the order of integration, that


Thus the function g(x) is increasing and it satisfies 0 < g(x) < 1. Further we have


Note that χψ is a primitive character (modDp). Write


so that


By (2.4) with θ = ψ and θ = χψ we have


This yields, by Stirling’s formula,


and


Lemma 4.4. Let


If s ∈ Ω3, then


Proof. By the residue theorem,


By (4.2) and (4.3),


By (3.5) and partial summation, the second sum on the right side above is


On the other hand, by the functional equation, for u = −σ − 1/2,


and


To prove (4.7) we move the contour of integration to the vertical segments



and to the two connecting horizontal segments


By a trivial bound for ω1(w), (4.5) and the residue theorem we obtain (4.7).


To prove (4.8) we move the contour of integration to the vertical segments


and to the two connecting horizontal segments


By a trivial bound for ω1(w) and (4.5) we see that the left side of (4.8) is


with s ∗ = 1 + α − s¯. By partial integration,


The estimate (4.9) follows by moving the contour of integration to the vertical segments


and to the two connecting horizontal segments


and applying (4.5) and trivial bounds for ω1(w) and the involved sum.


In order to prove Proposition 2.2, it is appropriate to deal with the function


By Lemma 4.2, A(s, ψ) is analytic and it has the same zeros as L(s, ψ)L(s, ψχ) in Ω1. Further, for s ∈ Ω1, we have


by Lemma 4.1 and 4.2. This together with Lemma 4.4 implies that


for s ∈ Ω3, where


The proof of Proposition 2.2 is reduced to proving three lemmas as follows.


Lemma 4.5. If


then


Proof. We discuss in two cases.


By Lemma 4.2 and trivial estimation,


Hence, by (4.5),


The result now follows by (4.10).


Since |B(1/2 + it, ψ)| = 1, it follows that


Hence, by (4.10),


Lemma 4.6. Suppose ρ = β + iγ is a zero of A(s, ψ) satisfying


Proof. It suffices to show that the function A(1/2 + iγ + w, ψ) has exactly one zero inside the circle |w| = α(1 − c ′αL), counted with multiplicity. By the Rouch´e theorem, this can be reduced to proving that


In either case (4.16) holds.


Lemma 4.5 and 4.6 together imply the assertions (i) and (ii) of Proposition 2.2. It is also proved that the gap between any distinct zeros of A(s, ψ) in Ω is > α(1 − c ′αL). To complete the proof of the gap assertion (iii), it now suffices to prove


Proof. In a way similar to the proof of Lemma 4.6, it is direct to verify that


We conclude this section by giving a result which is implied in the proof of Proposition 2.2.


Lemma 4.8. Assume that ρ is a zero of L(s, ψ)L(s, χψ) in Ω. Then we have


Proof. It follows from Lemma 4.4 that

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This paper is available on arxiv under CC 4.0 license.

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